x^2+3x+8=3x+3

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Solution for x^2+3x+8=3x+3 equation: 



x^2+3x+8=3x+3

We move all terms to the left:

x^2+3x+8-(3x+3)=0

We get rid of parentheses

x^2+3x-3x-3+8=0

We add all the numbers together, and all the variables

x^2+5=0

a = 1; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·1·5
Δ = -20
Delta is less than zero, so there is no solution for the equation

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